Resistor 81502

How big a series resistor do we need to connect to the LED if a voltage drop of 3.2 V is to be created on it and a current of 16 mA flows through the diode? We want to connect the diode to a voltage of 5V.

Correct answer:

R =  112.5 Ω

Step-by-step explanation:

U1=3.2 V I=16 mA A=16:1000  A=0.016 A U2=5 V  U3=U2U1=53.2=59=1.8 V  R=U3/I=1.8/0.016=112.5 Ω

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