Assembly time

The assembly time for the toy follows a normal distribution with a mean of 75 minutes and a standard deviation of 9 minutes. The company closes at 5 pm every day. If one starts assembling at 4 pm what is the probability that he will finish before the company closes for the day?

Correct result:

p =  0.0478

Solution:

m=75 min s=9 min  t1=60 (54)=60 min  p=N(x<t1,m,s)  p=0.0478=2395000



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