A 36

A 36 g sample of the substance contains 91% water. After drying, the weight of the sample was reduced to 18 g. What percentage of water is now in the sample?

Correct result:

p2 =  82 %

Solution:

m1=36 g p1=91%=91100=0.91 m2=18 g   s=m1 (1p1)=36 (10.91)=8125=3.24 g w2=m2s=183.24=36925=14.76  p2=100 w2m2=100 14.7618=82%



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