Eight chairs

There are eight chairs by the table and one more child sitting on each one. There are two times more girls than boys. How many girls and how many boys can there be?

Correct result:

d₁ =  2
c₁ =  1
d₂ =  4
c₂ =  2

Solution:

$d_1=2$

$$\begin{gathered} c_1=d_1\mathrm{/}2=2\mathrm{/}2=1 \\ {s}_1=d_1+c_1=2+1=3 \end{gathered}$$

$d_2=4$

$$\begin{gathered} c_2=d_2\mathrm{/}2=4\mathrm{/}2=2 \\ {s}_2=d_2+c_2=4+2=6 \end{gathered}$$

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