Content area and percents

Determine what percentage is smaller cube surface, when the surface area of the wall decreases by 25%.

Result

p =  25 %

Solution:

S2=(125/100)S1 6 S2=6(125/100)S1 p=25=25%S_{2}=(1-25/100) S_{1} \ \\ 6 \ S_{2}=6 (1-25/100) S_{1} \ \\ p=25=25 \%



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