Perpendicular 5865

We cut the cube with two mutually perpendicular cuts, each parallel to one of the cube's walls. By what percentage is the sum of the surfaces of all cuboids created in this way greater than the surface of the original cube?

Correct answer:

p =  66.6667 %

Step-by-step explanation:

S2 = 6 S1  S3 = 2 S1 + 2 S1 = 10   S1 p = (S3/S2  1)   100 p=(10/61) 100=66.6667%



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