He tile

The tile has the shape of an isosceles triangle, the base of which is 4 cm long, and the corresponding height is 6 cm long. At least how many tiles are needed to cover a wall containing 2.4 m²

Final Answer:

n =  2000

Step-by-step explanation:

$$\begin{gathered} a=4\text{cm} \\ v=6\text{cm} \\ S=2.4{\text{m}}^2\to {\text{cm}}^2=2.4\cdot 10000{\text{cm}}^2=24000{\text{cm}}^2 \\ {S}_1=\frac{a\cdot v}{2}=\frac{4\cdot 6}{2}=12{\text{cm}}^2 \\ n=\lceil S/S_1\rceil =\lceil 24000/12\rceil =2000 \end{gathered}$$

Try another example