Fertilizer

Meadow with an area of 1,500 square meters was fertilized with 12 kg of urea. Urea contains 45% nitrogen. How much nitrogen accounted per 1 m2?

Correct result:

x =  3.6 g

Solution:

m=12 1000=12000 g S=1500 m2 a=m/S=12000/1500=8 g/m2 x=45/100 a=45/100 8=185=185 g=3.6 g



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