Fertilizer

A meadow with an area of 1,500 m² was fertilised with 12 kg of urea. Urea contains 45% nitrogen. How much nitrogen was applied per 1 m²?

Final Answer:

x =  3.6 g

Step-by-step explanation:

$$\begin{gathered} m=12\text{kg}\to \text{g}=12\cdot 1000\text{g}=12000\text{g} \\ S=1500{\text{m}}^2 \\ a=m/S=12000/1500=8{\text{g/m}}^2 \\ p=45\%=\frac{45}{100}=\frac{9}{20}=0.45 \\ x=p\cdot a=0.45\cdot 8=3.6\text{g} \end{gathered}$$

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