Fertilizer

Meadow with an area of 1,500 square meters was fertilized with 12 kg of urea. Urea contains 45% nitrogen. How much nitrogen accounted per 1 m2?

Result

x =  3.6 g

Solution:

m=12 1000=12000 g S=1500 m2 a=m/S=12000/1500=8 g/m2 x=45/100 a=45/100 8=185=3.6 gm=12 \cdot \ 1000=12000 \ \text{g} \ \\ S=1500 \ \text{m}^2 \ \\ a=m/S=12000/1500=8 \ \text{g/m}^2 \ \\ x=45/100 \cdot \ a=45/100 \cdot \ 8=\dfrac{ 18 }{ 5 }=3.6 \ \text{g}



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