Operating 4230

The bearing has a lifespan of 8 years at a pressure of 4 bars and an operating time of 2 hours per day.
The bearing has a service life of 8 years at a pressure of 1.5 bar and an operating time of 14 hours a day.
What will be the service life of the bearing if it works 16 hours a day in both modes described above per day at the same time (14 + 2 hours)?

Correct answer:

x =  4 r

Step-by-step explanation:

x=8/2=4 r



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