Jewelry factory

In a jewelry factory, three assemblers make beaded necklaces.  Marcus can make 22 necklaces per hour all day long. Anita can make 25 necklaces for her first three hour of the days and then slow down to 16 necklaces for the rest of the day. Yara can make 27 necklaces per hour, but works a maximum of six hours a day  The factory gets a new order from a major retailer for 1000 necklaces at 8:00 am Monday.  Assuming   Marcus and Anita work 8 hours a day and Yara works her maximum, and   nobody works on the weekend,  what day and time will the order be fully assembled?

Result

d =  3
t = 8:02 hh:mm

Step-by-step explanation:

$$\begin{gathered} n=1000 \\ M=22 \\ {A}_1=25 \\ {A}_2=16 \\ Y=27 \\ {d}_1=M\cdot 8+3\cdot A_1+5\cdot A_2+6\cdot Y=22\cdot 8+3\cdot 25+5\cdot 16+6\cdot 27=493 \\ d=1+\lfloor n\mathrm{/}{d}_1\rfloor =1+\lfloor 1000\mathrm{/}493\rfloor =3 \\ Wednesday(Streda) \end{gathered}$$

$$\begin{gathered} r=n-d\cdot d_1=1000-3\cdot 493=-479 \\ t=8.00+{\displaystyle \frac{d}{M+A_1+A_2+Y}}=8.00+{\displaystyle \frac{3}{22+25+16+27}}={\displaystyle \frac{241}{30}}=8.03333=8:02\text{ hh}:\text{mm} \end{gathered}$$

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