Two aces

From a 32 card box we randomly pick 1 card and then 2 more cards. What is the probability that last two drawn cards are aces?

Correct result:

p =  1.2097 %

Solution:

a=(28/32)⋅ (4/31)⋅ (3/30)=7620≐0.0113 b=(4/32)⋅ (3/31)⋅ (2/30)=11240≐0.0008 p=100⋅ (a+b)=100⋅ (0.0113+0.0008)=7562=1.2097%

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