How many meters of rope 10 mm thick will fit on the bobbin diameter of 200 mm and length 350 mm (central mandrel have a diameter 50 mm)?

Correct result:

l =  313.4 m


a=10 D1=50 D2=200 x=350 n=(D2D1)/a=(20050)/10=15 o=π D x1=D1=50 d=2 a=2 10=20 x2=x1+(n1) d=50+(151) 20=330 s=(x1+x2)/2 n=(50+330)/2 15=2850 l1=π s=3.1416 28508953.5391 l2=l1/1000=8953.5391/10008.9535 m=x/a=350/10=35 l=m l2=35 8.9535=313.4 m

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