# Trucks

Three lorries droved bricks. One drove n bricks at once, second m less bricks than the first and third 300 bricks more the first lorry. The first lorry went 4 times a day the largest went 3 times a day and the smallest 5 times a day.

How many bricks brought:

a / all lorries in one day.
b / all lorries per week / Sunday don't worked /?

Result

a = (Correct answer is: 12n-5m+900)
b = (Correct answer is: 72n-30m+5400)

#### Solution:

$a=4n+3 \cdot \ (n+300)+5 \cdot \ (n-m) \ \\ a=12n-5m+900$
$b=6a \ \\ b=72n-30m+5400$

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