Three lorries droved bricks. One drove n bricks at once, the second m fewer bricks than the first and third 300 bricks more the first lorry. The first lorry went four times a day. The largest went three times a day, and the smallest lorry five times a day.

How many bricks were brought:

a / all lorries in one day.
b / all lorries per week (Sunday doesn't work)?

Correct answer:

a = 12n-5m+900
b = 72n-30m+5400

Step-by-step explanation:

a=4n+3 (n+300)+5 (nm) a=12n5m+900
b = 6a b=72n30m+5400

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