Bike path

Bill was riding his bike on a bike path that was 5 1/4 miles long. He rode his bike awhile and stopped for s drink or water. Then he rode 2 7/10 miles and was at the end of the path. How far had Bill ridden before he stopped for water?

Correct answer:

x =  2.55 mi

Step-by-step explanation:

$$\begin{gathered} a=5{\displaystyle \frac{1}{4}}=5+{\displaystyle \frac{1}{4}}={\displaystyle \frac{5\cdot 4+1}{4}}={\displaystyle \frac{21}{4}}=5.25\text{ mi } \\ b=2{\displaystyle \frac{7}{10}}=2+{\displaystyle \frac{7}{10}}={\displaystyle \frac{2\cdot 10+7}{10}}={\displaystyle \frac{27}{10}}=2.7\text{ mi } \\ x=a-b=5.25-2.7={\displaystyle \frac{51}{20}}\text{ mi}=2\frac{11}{20}\text{ mi}=2.55\text{ mi} \end{gathered}$$

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