Packets weight

The weight of three packets are 3 2/5 kg + 2 1/3 kg + 5 1/2 kg. Find total weight of all the three packets.

Correct answer:

m =  11.2333 kg

Step-by-step explanation:

$$\begin{gathered} a=3{\displaystyle \frac{2}{5}}=3+{\displaystyle \frac{2}{5}}={\displaystyle \frac{3\cdot 5+2}{5}}={\displaystyle \frac{17}{5}}=3.4\text{ kg } \\ b=2{\displaystyle \frac{1}{3}}=2+{\displaystyle \frac{1}{3}}={\displaystyle \frac{2\cdot 3+1}{3}}={\displaystyle \frac{7}{3}}\doteq 2.3333\text{ kg } \\ c=5{\displaystyle \frac{1}{2}}=5+{\displaystyle \frac{1}{2}}={\displaystyle \frac{5\cdot 2+1}{2}}={\displaystyle \frac{11}{2}}=5.5\text{ kg } \\ m=a+b+c=3.4+2.3333+5.5={\displaystyle \frac{337}{30}}\text{ kg}=11\frac{7}{30}\text{ kg}=11.2333\text{ kg} \end{gathered}$$

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