Material improvement

Material in a factory was originally enough for two workshops for 20 days. After implementing an efficiency improvement, the same material lasted 25 days. How many days will the material last for 5 workshops now? How many extra days of work do the saved materials provide with the new methods?

Final Answer:

t2 =  10 d
d =  2 d

Step-by-step explanation:

m1=2 20=40 m2=2 25=50 t1=m1/5=40/5=8 d t2=m2/5=50/5=10 d
d=t2t1=108=2 d



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