Find the average speed of a train (in km/h) that passes a telegraph pole in 7 seconds and passes a 378 m platform in 25 seconds. How long is the train?

Correct answer:

v =  75.6 km/h
l =  147 m

Step-by-step explanation:

t1=7 s t2=25 s n=378 m  v=s/t  v1 t1=l v1 t2=l+n v1 7=l v1 25=l+378  l7v1=0 l25v1=378  Row2Row1Row2 l7v1=0 18v1=378  v1=18378=21 l=0+7v1=0+7 21=147  l=147 v1=21  v=v1 km/h=v1 3.6  km/h=21 3.6  km/h=75.6 km/h   Verifying Solution:  T1=l/v1=147/21=7 s T2=(l+n)/v1=(147+378)/21=25 s

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