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On the construction site of a new housing estate in Kladno-Kročehlavy, students from the state labor reserve carried out machine plastering of the masonry. 5 students plastered 10 square meters more masonry than 6 plasterers who plastered by hand. Together, they plastered 960 square meters of masonry. What was the average performance of one worker with each method of plastering?

Correct answer:

a =  97
b =  79.1667

Step-by-step explanation:


5a = 10 + 6b
5a + 6b = 960

5·a = 10 + 6·b
5·a + 6·b = 960

5a-6b = 10
5a+6b = 960

Row 2 - Row 1 → Row 2
5a-6b = 10
12b = 950


b = 950/12 = 79.16666667
a = 10+6b/5 = 10+6 · 79.16666667/5 = 97

a = 97
b = 475/6 ≈ 79.166667

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