Cooker spiral

A current of 4.4 A flows through the spiral of the electric cooker. It is connected to a voltage of 220 V. What is the resistance of the spiral?

Correct answer:

R =  50 Ω

Step-by-step explanation:

U=220 V I=4.4 A  U = RI  R=U/I=220/4.4=50 Ω

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