Enlarged rectangle

The rectangle with dimensions of 8 cm and 12 cm is enlarged in a ratio of 5:4. What are the circumference and the area of the enlarged rectangle?

Result

o =  50 cm
S =  150 cm2

Solution:

a=8 cm b=12 cm  o1=2⋅ (a+b)=2⋅ (8+12)=40 cm k=54=1.25  o=k⋅ o1=1.25⋅ 40=50 cma=8 \ \text{cm} \ \\ b=12 \ \text{cm} \ \\ \ \\ o_{1}=2 \cdot \ (a+b)=2 \cdot \ (8+12)=40 \ \text{cm} \ \\ k=\dfrac{ 5 }{ 4 }=1.25 \ \\ \ \\ o=k \cdot \ o_{1}=1.25 \cdot \ 40=50 \ \text{cm}
S1=a⋅ b=8⋅ 12=96 cm2  S=k2⋅ S1=1.252⋅ 96=150 cm2S_{1}=a \cdot \ b=8 \cdot \ 12=96 \ \text{cm}^2 \ \\ \ \\ S=k^2 \cdot \ S_{1}=1.25^2 \cdot \ 96=150 \ \text{cm}^2

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