Two buses

The first bus runs 15 minutes the second bus runs after 21 minutes. Together they both leave at 7:00 on Monday. When and what day will they meet?

Result

t = 8:45 hh:mm Wrong answer

Solution:

15=3⋅5 21=3⋅7 LCM(15,21)=3⋅5⋅7=105  t1=LCM(15,21)=105 min t2=t1→ h=t1/60  h=105/60  h=1.75 h  t=7.00+t2=7.00+1.75=354=8.75=8:45 hh:mm

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