Ball acceleration distance

A ball placed on an inclined plane begins to move and reaches a speed of 1 m/s in 5 s. Assuming that the ball's motion is uniformly accelerated, determine the magnitude of its acceleration and the distance it travels in the given time.

Final Answer:

a =  0.2 m/s²
s =  2.5 m

Step-by-step explanation:

$$\begin{gathered} t=5\text{s} \\ v=1\text{m/s} \\ a=v/t=1/5=0.2{\text{m/s}}^2 \end{gathered}$$

$s=\frac{1}{2}\cdot a\cdot t^2=\frac{1}{2}\cdot 0.2\cdot 5^2=\frac{5}{2}\text{m}=2.5\text{m}$

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