Acceleration 7149

The body went through a uniformly accelerated path of 30 m in 10 seconds while its speed increased five times. Find the initial speed and acceleration.

Correct answer:

v =  0.8571 m/s
a =  0.4286 m/s2

Step-by-step explanation:

s=30 m t=10 s  s = vt + 0.5   a t2 at = 5v  s = at2/5 + 0.5 at2  a=t2/5+0.5 t2s=102/5+0.5 10230=730.4286 m/s2  v2=a t=73 10=73 10=7304.2857 m/s v=v2/5=730/5=7 530=3530=76 m/s=0.8571 m/s
a=73=0.4286 m/s2

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