CD compartment distribution

Thomas has two compartments with CD-ROMs. The arithmetic average of the number of CDs in both bins is 30. If he added 10 more CDs to the first bin, there would be 1.5 times more CDs than in the second bin. How many CDs are in each compartment?

Final Answer:

a =  32
b =  28

Step-by-step explanation:


(a+b)/2 = 30
a + 10 = 1.5 b

(a+b)/2 = 30
a + 10 = 1.5·b

a+b = 60
a-1.5b = -10

Row 2 - Row 1 → Row 2
a+b = 60
-2.5b = -70


b = -70/-2.5 = 28
a = 60-b = 60-28 = 32

a = 32
b = 28

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