Constant 7689

From cities A and B, two cars drive opposite each other on the same road. The first runs at a constant speed of 80 km/h, and the second at 60 km/h. How far will these cars be a quarter of an hour before the match?

Correct answer:

s =  35 km

Step-by-step explanation:

v1=80 km/h v2=60 km/h  t=1/4=41=0.25 h  s=(v1+v2) t=(80+60) 0.25=35 km



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