Passenger 1810

The distance between cities A and B is 165 km. A truck traveled from city A to city B at a speed of 50 km/h. Fifteen minutes later, a passenger drove from city B to city A at 72 km/h. How far will the passenger car travel before the two cars meet?

Correct answer:

s =  90 km

Step-by-step explanation:

50(t+15/60) + 72 t = 165
s = 72 t

50·(t+15/60) + 72·t = 165
s = 72·t

7320t = 9150
s-72t = 0

Pivot: Row 1 ↔ Row 2
s-72t = 0
7320t = 9150


t = 9150/7320 = 1.25
s = 0+72t = 0+72 · 1.25 = 90

s = 90
t = 5/4 = 1.25

Our linear equations calculator calculates it.

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