Car meeting distance

At 7:00 AM, a truck left town A at a speed of 40 km/h. Opposite him, a passenger car left town B at 8:30 AM at a speed of 70 km/h. The distance between cities A and B is 225 km. At what distance from city A will the two cars compete?

Final Answer:

x =  120 km

Step-by-step explanation:

v1=40 km/h v2=70 km/h  x+y= 225 x = v1(t7.00) y = v2(t8.5)  v1(t7.00)+v2(t8.5)=225 40(t7.00)+70(t8.5)=225  40 (t7.00)+70 (t8.5)=225  110t=1100  t=1101100=10  t=10  x=v1 (t7.00)=40 (107.00)=120 km



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