Freight and passenger car

The truck starts at 8 pm at 30 km/h. Passenger car starts at 8 pm at 40 km/h. Passenger arrives in the destination city 1 hour and 45 min earlier. What is the distance between the city of departure and destination city?

Correct result:

s =  210 km

Solution:

30 t = 40 (t-1.75)
s = 30 t

30•t = 40•(t-1.75)
s = 30•t

10t = 70
s-30t = 0

s = 210
t = 7

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