Two cities

Cities A and B are 200 km away. At 7 o'clock from city A, the car started at an average speed of 80 km/h, and from B at 45 min later the motorcycle is started at an average speed of 120 km/h. How long will they meet and at what distance from the point A it will be?

Result

t = 8:27 h
s =  116 km

Solution:

$$\begin{gathered} 200=80\cdot (T-7.00)+120\cdot (T-7.00-45\mathrm{/}60) \\ 12000T=101400 \\ T={\displaystyle \frac{169}{20}}=8.45 \\ t=T=8.45={\displaystyle \frac{169}{20}}=8:27\text{ h} \end{gathered}$$

$s=80\cdot (T-7.00)=80\cdot (8.45-7.00)=116\text{ km}$

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