Two cities

Cities A and B are 200 km away. At 7 o'clock from city A, the car started at an average speed of 80 km/h, and from B at 45 min later the motorcycle is started at an average speed of 120 km/h. How long will they meet and at what distance from the point A it will be?

Result

t = 8:27 h Wrong answer
s =  116 km

Solution:

 200=80⋅ (T−7.00)+120⋅ (T−7.00−45/60)  12000T=101400  T=16920=8.45  t=T=8.45=16920=8:27 h \ \\ 200=80 \cdot \ (T-7.00) + 120 \cdot \ (T-7.00-45/60) \ \\ \ \\ 12000T=101400 \ \\ \ \\ T=\dfrac{ 169 }{ 20 }=8.45 \ \\ \ \\ t=T=8.45=\dfrac{ 169 }{ 20 }=8:27 \ \text{h}
s=80⋅ (T−7.00)=80⋅ (8.45−7.00)=116 kms=80 \cdot \ (T-7.00)=80 \cdot \ (8.45-7.00)=116 \ \text{km}

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