# Two cities

Cities A and B are 200 km away. At 7 o'clock from city A, the car started at an average speed of 80 km/h, and from B at 45 min later the motorcycle is started at an average speed of 120 km/h. How long will they meet and at what distance from the point A it will be?

Result

t = 8:27 h
s =  116 km

#### Solution:

$\ \\ 200=80 \cdot \ (T-7.00) + 120 \cdot \ (T-7.00-45/60) \ \\ \ \\ 12000T=101400 \ \\ \ \\ T=\dfrac{ 169 }{ 20 }=8.45 \ \\ \ \\ t=T=8.45=\dfrac{ 169 }{ 20 }=8:27 \ \text{h}$
$s=80 \cdot \ (T-7.00)=80 \cdot \ (8.45-7.00)=116 \ \text{km}$

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