Simultaneously 68864

From cities A and B, which are 50 km apart, two cars set off in the same direction simultaneously with average speeds of 80 km/h and 120 km/h. How long will the faster car reach, the slower one, and at what distance from city A?

Correct answer:

t =  0.25 h
s1 =  20 km

Step-by-step explanation:

s=50 km v1=80 km/h v2=120 km/h  s=v t t=v1+v2s=80+12050=41 h=0.25 h
s1=v1 t=80 41=480 1=480=20 km

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