Cars 2

Opava is 360 km distance from Prešov. At 8:00 hour two cars started against each other from this cities at average speeds 88 km/h and 121 km/h.

At what hour its will meet and what distance its travel if car started from Prešov is faster?

Result

T = 9:43 hh:mm
s₁ =  151.58 km
s₂ =  208.42 km

Solution:

$$\begin{gathered} s_1=v_{1}t \\ {s}_2=v_{2}t \\ s=s_1+s_2=v_{1}t+v_{2}t=t(v_1+v_2) \\ t={\displaystyle \frac{s}{v_1+v_2}}={\displaystyle \frac{360}{88+121}}=1.72h \\ T=8+t=9:43\text{ hh}:\text{mm} \end{gathered}$$

$s_1=v_{1}t=88\cdot 1.72=151.58\text{ km}$

$s_2=v_{2}t=121\cdot 1.72=208.42\text{ km}$

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