# Cars 2

Opava is 360 km distance from Prešov. At 8:00 hour two cars started against each other from this cities at average speeds 88 km/h and 121 km/h.

At what hour its will meet and what distance its travel if car started from Prešov is faster?

Result

T = 9:43 hh:mm
s1 =  151.58 km
s2 =  208.42 km

#### Solution:

$s_1 = v_1 t \ \\ s_2 = v_2 t \ \\ s = s_1+s_2 = v_1 t + v_2 t = t(v_1+v_2) \ \\ t = \dfrac{s}{v_1+v_2} = \dfrac{ 360}{ 88+121 } = 1.72 \ h \ \\ T = 8 + t = 9:43 \ \text{hh}:\text{mm}$
$s_1 = v_1 t = 88 \cdot 1.72 = 151.58 \ \text{km}$
$s_2 = v_2 t = 121 \cdot 1.72 = 208.42 \ \text{km}$

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