Against each other

From two points A, B distant 23 km at the same time started two cars against each other at speeds 41 km/h and 65 km/h. How long does cars meet and what distance passes each of them?

Correct answer:

t =  13 min
s₁ =  8.9 km
s₂ =  14.1 km

Step-by-step explanation:

$$\begin{gathered} t={\displaystyle \frac{s}{v_1+v_2}}={\displaystyle \frac{23}{41+65}} \\ t=0.217h=13\text{ min} \end{gathered}$$

$s_1=v_1\cdot t=41\cdot 0.217=8.9\text{ km}$

$s_2=v_2\cdot t=65\cdot 0.217=14.1\text{ km}$

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