Against each other

From two points A, B distant 23 km at the same time started two cars against each other at speeds 41 km/h and 65 km/h. How long does cars meet and what distance passes each of them?

Result

t =  13 min
s₁ =  8.9 km
s₂ =  14.1 km

Solution:

$t = \dfrac{s}{v_1+v_2} = \dfrac{ 23}{ 41+ 65 } \ \\ t = 0.217 \ h = 13 \ \text{min}$

$s_1 = v_1 \cdot t = 41 \cdot 0.217 = 8.9 \ \text{km}$

$s_2 = v_2 \cdot t = 65 \cdot 0.217 = 14.1 \ \text{km}$

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