Cyclist meeting

From Děčín and Ústí nad Labem, which are 24 km apart, two cyclists rode against each other at the same time. One drove at an average speed of 28 km/h, and the other, which left Ústí, drove at a speed of 20 km/h. How long did the cyclists meet, and at what distance from Děčín?

Final Answer:

t =  0.5 h
s1 =  14 km

Step-by-step explanation:

s=24 km v1=28 km/h v2=20 km/h  s = s1+s2 s = t v1+t v2  t=v1+v2s=28+2024=0.5 h
s1=v1 t=28 0.5=14 km



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