Two friends

Two friends on a bicycle rode against each other from two places 49 km apart. The first set off at 8.00 at a speed of 20km/h, the second 12 minutes later at a speed of 25km/h. What time do they meet? How many km will each of them travel since then?

Result

t = 9:12 Wrong answer
a =  24 km
b =  25 km

Step-by-step explanation:

s=49 km v1=20 km/h v2=25 km/h t1=8.00 h t2=86012=8+6012=608 60+12=60492=541=851=8.2 h  a+b=s a=v1 (tt1) b=v2 (tt2) a+b=49 a=20 (t8) b=25 (t8.2)  a+b=49 a20t=160 b25t=205  Row2Row1Row2 a+b=49 b20t=209 b25t=205  Row3+Row2Row3 a+b=49 b20t=209 45t=414  t=45414=9.2 b=1209+20t=1209+20 9.2=25 a=49b=4925=24  a=24 b=25 t=546=9.2=9:12
a=24=24 km
b=25=25 km



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