Two friends

Two friends on a bicycle rode against each other from two places 49 km apart. The first set off at 8.00 at a speed of 20km/h, the second 12 minutes later at a speed of 25km/h. What time do they meet? How many km will each of them travel since then?

Result

t = 9:12 Wrong answer
a =  24 km
b =  25 km

Step-by-step explanation:

s=49 km v1=20 km/h v2=25 km/h t1=8.00 h t2=81260=8+1260=8 60+1260=49260=415=815=8.2 h  a+b=s a=v1 (tt1) b=v2 (tt2) a+b=49 a=20 (t8) b=25 (t8.2)  a+b=49 a20t=160 b25t=205  a=24 b=25 t=465=9.2=9.2=9:12
a=24=24 km
b=25=25 km



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