Distances

On the way from Bratislava to Trebišov (440 km), 2 cars set off towards each other. The car from BA set off at 8:00 a.m. and the car from Trebišov at 9:00 a.m. They met at 11:00 a.m., the car from Trebišov traveled 25 km less than the second car each hour. What were the average speeds of both cars and at what distance from Trebišov did they meet.

Correct answer:

v1 =  98 km/h
v2 =  73 km/h
s2 =  146 km

Step-by-step explanation:


v1 = 25 + v2
440 = v1 · (11.00-8.00) + v2·(11.00-9.00)

v1-v2 = 25
3v1+2v2 = 440

Pivot: Row 1 ↔ Row 2
3v1+2v2 = 440
v1-v2 = 25

Row 2 - 1/3 · Row 1 → Row 2
3v1+2v2 = 440
-1.67v2 = -121.67


v2 = -121.66666667/-1.66666667 = 73
v1 = 440-2v2/3 = 440-2 · 73/3 = 98

v1 = 98
v2 = 73

Our linear equations calculator calculates it.
v2=73=73 km/h
s2=v2 (11.009.00)=73 (11.009.00)=146 km



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