Motion against

From two places 36 km apart, a pedestrian and a cyclist will go straight opposite each other. How long will they meet if the speed of the pedestrian is 4 km/h and the cyclist 12 km/h?

Correct result:

t =  2.25 h

Solution:

v1=4 km/h v2=12 km/h s=36 km  v=v1+v2=4+12=16 km/h  t=s/v=36/16=94=94 h=2.25 h



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