Simultaneously 41451

Cities A and B are 36 km apart. A pedestrian leaves town A at a speed of 6 km/h to place B. A cyclist leaves town B simultaneously at a speed of 24 km/h to town A. In how many hours and at what distance will they meet? Write the result in minutes.

Correct answer:

t =  1.2 h
m =  72 min
s1 =  7.2 km
s2 =  28.8 km

Step-by-step explanation:

v1=6 km/h v2=24 km/h s=36 km  v=v1+v2=6+24=30 km/h  t=s/v=36/30=1.2 h
m=t min=t 60  min=1.2 60  min=72 min=72 min
s1=v1 t=6 1.2=7.2 km
s2=v2 t=24 1.2=28.8 km

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