Pedestrian 43761

From two places A and B 27 km apart, a pedestrian will walk at the same time at a speed of 6 km / h from place A, a cyclist at a rate of 24 km / h from place B. At what distance from place A will they compete?

Correct answer:

x =  5.4 km

Step-by-step explanation:

s=27 km v1=6 km/h v2=24 km/h v=v1+v2=6+24=30 km/h  t=s/v=27/30=109=0.9 h  x=v1 t=v1 109=6 0.9=5.4 km



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