Direction 82705

A cyclist left Olomouc in the direction of Zábřeh in 6 h 30 min at an average speed of 24 km/h. At 7:40 a.m., a cyclist left Olomouc opposite Ostrava at an average 36 km/h rate. At what time will they be 112 km apart?

Result

t = 9:04 hh:mm Wrong answer

Step-by-step explanation:

t1=6:30=6 hr 30 min =6+6030=6.5 hr=6.5 t2=7:40=7 hr 40 min =7+6040=7.6667 hr7.6667 v1=24 km/h v2=36 km/h  s=112 km s=s1+s2  s=v1 (tt1)+v2 (tt2) 112=24 (t6.5)+36 (t7.6666666666667)  60t=544  t=60544=9.06666667  t=151369.066667=9.06667=9:04 hh:mm



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