Two places

The distance to the places is 60 km. From A place, a pedestrian came out at a speed of 4 km/h, and at the same time, a car drove against him from place B. What was the car's speed if the pedestrian met him in 90 minutes?

Correct answer:

v =  36 km/h

Step-by-step explanation:

s=60 km v1=4 km/h t=90 min h=90:60  h=1.5 h  s=v1 t+v t 60=4 1.5+v 1.5  1.5v=54  v=1.554=36  v=36=36 km/h



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