Two places

The distance to the places is 60 km. From place A a pedestrian came out at a speed of 4 km/h and at the same time a car drove against him from place B. What was the speed of the car if the pedestrian met him in 90 minutes?

Correct result:

v =  36 km/h

Solution:

s=60 km v1=4 km/h t=90 min h=90/60  h=1.5 h    s=v1 t+v t 60=4 1.5+v 1.5  1.5v=54  v=36=36 km/h



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