Two walkers simultaneously started against each other from places A and B. After meeting, both continued to B. Second walker came to B 2 hours before the first walker. Its speed is 2.7 times of the speed of the first pedestrian.

How many hours went pedestrians before they met?

Correct answer:

t =  1.2 h

Step-by-step explanation:

v1=1km/h v2=2.7v1=2.7km/h  x=v1t=v2(t2) v1t1=v2t2v2 t(v1v2)=2v2  t=v2v12v2=2.712 t=1.2 h

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