# Walkers

From points A and B simultaneously started against each other two walkers. After meeting both continue to B. Second walker came to B 2 hours before the first walker. It's speed is 2.7 times of speed of the first pedestrian.

How many hours went pedestrians before they met?

Result

t =  1.2 h

#### Solution:

$v_1 = 1 km/h \ \\ v_2 = 2.7 v_1 = 2.7 km/h \ \\ \ \\ x = v_1 t = v_2 (t- 2) \ \\ v_1 t_1 = v_2 t - 2 \cdot v_2 \ \\ t(v_1 - v_2) = - 2 \cdot v_2 \ \\ \ \\ t = \dfrac{ 2 \cdot v_2 }{ v_2 - v_1 } = \dfrac{ 2 }{ 2.7-1 } \ \\ t = 1.2 \ \text{h}$

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