Two cars

Two cars started against each other at the same time to journey long 346 km. The first car went 53 km/h and the second 53 km/h.

What distance will be between these cars 20 minutes before meet?

Result

x =  35.33 km

Solution:

v1=53 km/h v2=53 km/h s=346 km  T=20 min=20/60 h=0.33333 h  0<x<s x=v1 T+v2 T=53 0.3333+53 0.3333106335.333335.33 kmv_{1}=53 \ \text{km/h} \ \\ v_{2}=53 \ \text{km/h} \ \\ s=346 \ \text{km} \ \\ \ \\ T=20 \ min=20 / 60 \ h=0.33333 \ h \ \\ \ \\ 0 \lt x \lt s \ \\ x=v_{1} \cdot \ T + v_{2} \cdot \ T=53 \cdot \ 0.3333 + 53 \cdot \ 0.3333 \doteq \dfrac{ 106 }{ 3 } \doteq 35.3333 \doteq 35.33 \ \text{km}



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