Motion

Cyclist started at 9:00 from point S to point T. After 10 minutes, followed him at the same speed the second cyclist. Walker, which went from T to S, started at 9:35. After 71 minutes he met the first cyclist and after next 8 minutes the second cyclist.
Distance between the two cities is 37 km.

Determine the (same) speed of cyclists and walker.

Result

v1 =  17.9 km/h
v2 =  4.5 km/h

Solution:

Solution in text v__1 =
Solution in text v__2 =

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To solve this verbal math problem are needed these knowledge from mathematics:

Do you have a linear equation or system of equations and looking for its solution? Or do you have quadratic equation? Do you want to convert length units?

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