Two cities

The distance between cities A and B is 132 km. At 9.00 am, the cyclist started the bike at an average speed of 24 km/h, and at 10.00 h started from the B cyclist at an average speed of 30 km/h. How long and far from A will they both meet?

Correct result:

t =  12 hh:mm
s1 =  72 km

Solution:


24(t-9.00) + 30(t-10.00)=132

24•(t-9.00) + 30•(t-10.00)=132

54t = 648

t = 12

Our simple equation calculator calculates it.
s1=24 (t9.00)=24 (129.00)=72 km



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