Two cities

The distance between cities A and B is 132 km. At 9.00 am, the cyclist started the bike at an average speed of 24 km/h, and at 10.00 h started from the B cyclist at an average speed of 30 km/h. How long and far from A will they both meet?

Result

t =  12 hh:mm
s1 =  72 km

Solution:


24(t-9.00) + 30(t-10.00)=132

54t = 648

t = 12

Calculated by our simple equation calculator.
s1=24 (t9.00)=24 (129.00)=72 kms_{1}=24 \cdot \ (t-9.00)=24 \cdot \ (12-9.00)=72 \ \text{km}



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