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The distance between the two airports is 3480 km. There are regular connections from airport 1. The plane takes off at 6:30 am at an average speed of 600 km/h. From airport two at 7:00 am at a speed of 540 km/h. When will they meet?

Result

t = 9:27 hh:mm Wrong answer

Step-by-step explanation:


600·(t-6.50)+700·(t-7.00) = 3480

1300t = 12280


t = 12280/1300 = 9.44615385

t = 614/65 ≈ 9.446154

Our simple equation calculator calculates it.



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