Plane meeting

The distance between the two airports is 3480 km. There are regular connections from airport 1. The plane takes off at 6:30 am at an average speed of 600 km/h. From airport two at 7:00 am at a speed of 540 km/h. When will they meet?

Result

t = 9:27 hh:mm Wrong answer

Step-by-step explanation:

v1=600 km/h v2=700 km/h s=3480 km  s1+s2=s  v1 (t6.50)+v2 (t7.00)=s 600 (t6.50)+700 (t7.00)=3480  1300t=12280  t=130012280=9.44615385  t=656149.446154=9.44615=9:27 hh:mm



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