Two ships

The distance from A to B is 300km. At 7 am started from A to B a ferry with speed higher by 20 km/h than a ship that leaves at 8 o'clock from B to A. Both met at 10h 24min. Determine how far they will meet from A and when they reach the destination.

Result

s1 =  204 km
t1 = 12:00 hh:mm Wrong answer
t2 = 15:30 hh:mm Wrong answer

Step-by-step explanation:

s=300 km s1+s2=s s1=(v+20)t s2=v(t1)  t=(10+24/60)7.00=517=3.4 h  (v+20)t+v(t1)=300  3.4 (v+20)+v 2.4=300 5.8v=232 529v=232 29v=1160 v=1160/29=40  s1=(v+20) t=(40+20) 3.4=204 km
t1=7.00+s/(v+20)=7.00+300/(40+20)=12=12:00 hh:mm
t2=8.00+s/v=8.00+300/40=231=15.5=15:30 hh:mm



Did you find an error or inaccuracy? Feel free to write us. Thank you!










Tips to related online calculators
Do you have a linear equation or system of equations and looking for its solution? Or do you have a quadratic equation?
Do you want to convert length units?
Do you want to convert velocity (speed) units?
Do you want to convert time units like minutes to seconds?

Related math problems and questions: