Calculate 7572

At eight in the morning, a cyclist went from city K to city L. He stayed in city L for 4.25 hours and returned home at 3:00 p.m. Calculate the distance between cities K and L if the cyclist traveled to city L at a speed of 12 km/h and from city L to city K at a speed of 10 km/h.

Correct answer:

s =  15 km

Step-by-step explanation:


s = 12 · t
s = 10 · (15-8-4.25-t)

s-12t = 0
s+10t = 27.5

Row 2 - Row 1 → Row 2
s-12t = 0
22t = 27.5


t = 27.5/22 = 1.25
s = 0+12t = 0+12 · 1.25 = 15

s = 15
t = 5/4 = 1.25

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