Cyclist Round Trip Distance

At eight in the morning, a cyclist went from city K to city L. He stayed in city L for 4.25 hours and returned home at 3:00 p.m. Calculate the distance between cities K and L if the cyclist traveled to city L at a speed of 12 km/h and from city L to city K at a speed of 10 km/h.

Final Answer:

s =  15 km

Step-by-step explanation:

v1=12 km/h v2=10 km/h  s = v1   t s = v2   (1584.25t)  v1 t=v2 (1584.25t) 12 t=10 (1584.25t)  22t=27.5  t=2227.5=1.25  t=45=1.25  s=v1 t=12 1.25=15 km



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algebrabasic operations and conceptsUnits of physical quantitiesthemes, topicsGrade of the word problem

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