Two trucks

Two trucks left cities A and B against each other and met after an hour. The first car came to B 27 minutes later than the second car to A. Calculate the car speed if the distance between cities A, B is 90 km.

Correct result:

v1 =  40 km/h
v2 =  50 km/h

Solution:

s=90 km  t1=1 h t2=27 min h=27/60  h=0.45 h  s1+s2=s  v1 t1+v2 t1=s v1 (t+t2)=s v2 t=s  1 v1+1 v2=90 v1 (t+27/60)=90 v2 t=90  v1+v2=90 v1 t+v1 27/60=90 t=90/v2  v1+v2=90 v1 90/v2+v1 27/60=90  v1 90+v2 v1 27/60=90 v2 (90v2) 90+v2 (90v2) 27/60=90 v2  (90x)9060+x(90x)27=6090x  (90x) 90 60+x (90x) 27=60 90 x 27x28370x+486000=0 27x2+8370x486000=0  a=27;b=8370;c=486000 D=b24ac=83702427(486000)=122544900 D>0  x1,2=b±D2a=8370±12254490054 x1,2=8370±1107054 x1,2=155±205 x1=50 x2=360   Factored form of the equation:  27(x50)(x+360)=0  v2=x1=50 v1=90v2=9050=40 km/h

Our quadratic equation calculator calculates it.

v2=50=50 km/h



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