Cyclists 13831

Two cyclists left one place on the circuit facing each other. The first drove at a speed of 32 km/h and the second at 28 km/h. How long was the circuit if the cyclists met in 5 minutes?

Correct answer:

s =  5000 m

Step-by-step explanation:

v1=32 km/h m/s=32:3.6  m/s=8.88889 m/s v2=28 km/h m/s=28:3.6  m/s=7.77778 m/s t=5 min s=5 60  s=300 s  s=(v1+v2) t=(980+970) t=(8.8889+7.7778) 300=5000 m



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