Cyclist speed

Two cyclists set out simultaneously toward each other from opposite ends of a 28 km route. Each rode at a constant speed, with the faster cyclist reaching the finish line 35 minutes earlier. The cyclists passed each other after 1 hour of riding. At what speed was the slower cyclist going?

Final Answer:

v1 =  16 km/h

Step-by-step explanation:

s=28 km Δ=35 min h=35:60  h=0.58333 h T=1 h  s = v1   t s = v2   (t + Δ)  s1+s2 = s s1 = v1   T s2 = v2   T  s1=16 km s2=ss1=2816=12 km t=7/4=47=1.75 h v1=16 km/h v1=v2=28v1=2816=12 km/h=16 km/h



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algebraarithmeticUnits of physical quantitiesthemes, topicsGrade of the word problem

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